Exams › JEE Advanced › Maths
How many solutions does the equation 16(sin⁵(x) + cos⁵(x)) = 11(sin(x) + cos(x)) have in the interval [0, 2*pi]?
- 6
- 7
- 8
- 9
Correct answer: 6
Solution
Setting t = sin(x)+cos(x), the equation splits into t = 0 (giving 2 solutions) and t = +/-sqrt(6)/2 (giving 2+2 solutions), for a total of 6 in [0, 2*pi].
Related JEE Advanced Maths questions
⚔️ Practice JEE Advanced Maths free + battle 1v1 →