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Four containers each hold 3 red balls and 2 blue balls, with all 20 balls being unique. In how many ways can 10 balls be selected such that at least one red ball and one blue ball are picked from every container?
- 21816
- 85536
- 12096
- 156816
Correct answer: 21816
Solution
The selection of balls ensures at least one red and one blue ball from each container. Using combinatorics, the total number of ways to achieve this is calculated as 21816.
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