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Three nonnegative integers x, y, and z are selected at random such that their sum equals 10. What is the likelihood that z is an even number?
- 1/2
- 36/55
- 5/11
- 6/11
Correct answer: 6/11
Solution
The likelihood that z is an even number can be calculated by considering all possible combinations of nonnegative integers x, y, and z that sum to 10 and then determining the number of cases where z is even, resulting in a probability of 6/11.
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