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What is the cubic equation formed when r₁, r₂, and r₃ are the roots?

1. x³ - (R + r)x² + sx - rs² = 0
2. x³ - (R - 2r)x² + sx - rs² = 0
3. x³ - (4R + r)x² + sx - rs² = 0
4. x³ - 4(R + r)x² + sx - rs² = 0

Correct answer: x³ - (R + r)x² + sx - rs² = 0

Solution

The cubic equation is derived using the roots r₁, r₂, and r₃ and their relationships to the coefficients. Substituting these relationships confirms the equation x³ - (R + r)x² + sx - rs² = 0.

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