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Two individuals, A and B, take turns shooting at their targets independently until they succeed. The likelihood of A hitting the target in a single attempt is 3/5, while for B it is 5/7. What is the probability that A will hit the target in fewer attempts than B?

1. 6/31
2. 7/31
3. 8/31
4. 1/2

Correct answer: 6/31

Solution

The probability of A hitting the target in fewer attempts than B is calculated using geometric probability distributions for independent events. The result simplifies to 6/31.

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