Exams › JEE Advanced › Maths › Basic Algebra (Equations)
2 questions with worked solutions.
Q1. Solve the equation sqrt(2x + 1) = sqrt(x) + 1 for x.
Answer: x = 0 or x = 4
Square: 2x + 1 = x + 2sqrt(x) + 1 ⇒ x = 2sqrt(x) ⇒ x - 2sqrt(x) = 0 ⇒ sqrt(x)(sqrt(x) - 2) = 0 ⇒ sqrt(x) = 0 or 2 ⇒ x = 0 or x = 4. Both satisfy the original (x=0: sqrt(1)=1=0+1 ✓; x=4: sqrt(9)=3=2+1 ✓).
Q2. Solve |2x - 3| + 4 = 2 for real x.
Answer: no solution
Isolating gives |2x - 3| = -2. Since an absolute value is always >= 0, it can never equal -2. Therefore there is no real solution.