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ExamsJEE AdvancedGeneral

A light ray is incident on the surface of a sphere of refractive index n at an angle of incidence   . The ray partially refracts into the sphere with angle of refraction   and then partly reflects from the back surface. The reflected ray then emerges out of the sphere after a partial refraction. The total angle of deviation of the emergent ray with respect to the incident ray is  . Match the quantities mentioned in List-I with their values in List-II and choose the correct option. List-I List-II (P) If n = 2 and  = 180°, then all the possible values of   will be (1) 30° and 0° (Q) If n = 3 and  = 180°, then all the possible values of   will be (2) 60° and 0° (R) If n = 3 and  = 180°, then all the possible values of   will be (3) 45° and 0° (S) If n = 2 and  0 = 45°, then all the possible values of  will be (4) 150° (5) 0°

  1. P  5; Q  2; R  1; S  4
  2. P  5; Q  1; R  2; S  4
  3. P  3; Q  2; R  1; S  4
  4. P  3; Q  1; R  2; S  5

Correct answer: P  5; Q  2; R  1; S  4

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