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A block of mass 5 kg moves along the x -direction subject to the force F = (–20x + 10) N, with the value of x in metre. At time t = 0 s, it is at rest at position x = 1 m. The position and momentum to the block at t = (  ) s are

–0.5 m, 5 kg m/s
0.5 m, 0 kg m/s
0.5 m, –5 kg m/s 
–1 m, 5 kg m/s

Correct answer: 0.5 m, –5 kg m/s 

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