Exams › JEE Advanced › General
For any y R, let cot – 1 (y) (0, ) and tan – 1 (y) 2 , 2 . Then the sum of all the solutions of the equation tan – 1 2 y 9 y 6 + cot – 1 y 6 y 9 2 = 3 2 for 0 < |y| < 3, is equal to
- 2 3 – 3
- 3 – 2 3
- 4 3 – 6
- 6 – 4 3
Correct answer: 4 3 – 6
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