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Let , and be real numbers. Consider the following system of linear equations x + 2y + z = 7 x + z = 11 2x – 3y + z = Match each entry in Li st - I to the correct entries in List - II. List - I List - II (P) If = 2 1 (7 – 3) and = 28, then the system has (1) a unique solution (Q) If = 2 1 (7 – 3) and 28, then the system has (2) no solution (R) If 2 1 (7 – 3) where = 1 and 28, then the system has (3) infinitely many solutions (S) If 2 1 (7 – 3) where = 1 and = 28, then the system has (4) x = 11, y = – 2 and z = 0 as a solution (5) x = – 1 5, y = 4 and z = 0 as a solution The correct option is:
- (P) (3) ; (Q) (2) ; (R) (1) ; (S) (4)
- (P) (3) ; (Q) (2) ; (R) (5) ; (S) (4)
- (P) (2) ; (Q) (1) ; (R) (4) ; (S) (5)
- (P) (2) ; (Q) (1) ; (R) (1) ; (S) (3)
Correct answer: (P) (3) ; (Q) (2) ; (R) (1) ; (S) (4)
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