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For the following reaction CH 4 (g) + Cl 2 (g) ⎯ ⎯ → ⎯ light CH 3 Cl(g) + HCl (g) the correct statement is

1. Initiation step is exothermic with Δ H° = – 58 kcal mol –1 .
2. Propagation step involving • CH 3 formation is exothermic with Δ H° = – 2 kcal mol –1 .
3. Propagation step involving CH 3 Cl formation is endothermic with Δ H° = + 27 kcal mol –1 .
4. The reaction is exothermic with Δ H° = –25 kcal mol –1 .

Correct answer: The reaction is exothermic with Δ H° = –25 kcal mol –1 .

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