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Consider a triangle Δ whose two sides lie on the x-axis and the line x + y + 1 = 0. If the orthocenter of Δ is (1, 1), then the equation of the circle passing through the vertices of the triangle Δ is

x 2 + y 2 – 3x + y = 0
x 2 + y 2 + x + 3y = 0
x 2 + y 2 + 2y – 1 = 0
x 2 + y 2 + x + y = 0

Correct answer: x 2 + y 2 + x + 3y = 0

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