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ExamsJEE AdvancedGeneral

Match each set of hybrid orbitals from LIST-I with complex(es) given in LIST-II. LIST-I LIST-II P. dsp 2 1. [FeF 6 ] 4– Q. sp 3 2. [Ti(H 2 O) 3 Cl 3 ] R. sp 3 d 2 3. [Cr(NH 3 ) 6 ] 3+ S. d 2 sp 2 4. [FeCl 4 ] 2– 5. Ni(CO) 4 6. [Ni(CN) 4 ] 2– The correct option is :

  1. P → 5; Q → 4,6; R → 2,3; S → 1
  2. P → 5,6; Q → 4; R → 3; S → 1,2
  3. P → 6; Q → 4,5; R → 1; S → 2,3
  4. P → 4,6; Q → 5,6; R → 1,2; S → 3

Correct answer: P → 6; Q → 4,5; R → 1; S → 2,3

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