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The equation of the plane passing through the point (1, 1, 1) and perpendicular to the planes 2x + y – 2z = 5 and 3x – 6y – 2z = 7, is

14x + 2y + 15z = 31
14x – 2y + 15z = 27
–14x + 2y + 15z = 3
14x + 2y – 15z = 1

Correct answer: 14x + 2y + 15z = 31

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