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The standard state Gibbs free energies of formation of C (Graphite) and C (diamond) at T = 298 K are Δ f G º [C(graphite)] = 0 kj mil –1 Δ f G º [C(diamond)] = 2.9 kj mil –1 The standard state means that the pressure should be 1 bar, and substance should be pure at a given temperature. The conversing of graphite [C(graphite)] to diamond [C(diamond)] reduces its volume by 2 × 10 –6 m 3 mol –1 . If C(graphite) is converted to C(diamond) isothermally at T = 298 K, the pressure at which C(graphite) is in equilibrium with C(diamond), is [Useful information: 1 J = 1 kg m 2 s –2 ; 1 Pa = 1 kg m –1 s –2 ; bar = 10 5 Pa]

1. 29001 bar
2. 1450 bar
3. 14501 bar
4. 58001 bar

Correct answer: 14501 bar

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