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Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethanol to 500 g of water changes the freezing point of the solution. Use the freezing point depression constant of water as 2 K kg mol –1 . The figures shown below represent plots of vapour pressure (V.P.) versus temperature (T). [molecular weight of ethanol is 46 g mol –1 ]. Among the following, the option representing change in the freezing point is -

1. Water Water + Ethanol V.P./Bar 270 273 T/K Ice I –
2. Water Water + Ethanol V.P./Bar 270 273 T/K Ice I –
3. Water Water + Ethanol V.P./Bar 271 273 T/K Ice I –
4. Water Water + Ethanol V.P./Bar 271 273 T/K Ice I – CAREER POINT CAREER POINT , CP Tower, IPIA, Road No.1, Kota (Raj.), : 0744-6630500 | www.ecareerpoint.com Email: info@cpil.in Page # 23 Paper-2 [ CODE – 5 ]

Correct answer: Water Water + Ethanol V.P./Bar 270 273 T/K Ice I –

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