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The order of the oxidation state of the phosphorus atom in H 3 PO 2 , H 3 PO 4 , H 3 PO 3 , and H 4 P 2 O 6 is -

H 3 PO 3 > H 3 PO 2 > H 3 PO 4 > H 4 P 2 O 6
H 3 PO 4 > H 3 PO 2 > H 3 PO 3 > H 4 P 2 O 6
H 3 PO 2 > H 3 PO 3 > H 4 P 2 O 6 > H 3 PO 4
H 3 PO 4 > H 4 P 2 O 6 > H 3 PO 3 > H 3 PO 2

Correct answer: H 3 PO 4 > H 4 P 2 O 6 > H 3 PO 3 > H 3 PO 2

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