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A rocket is launched normal to the surface of the Earth, away from the Sun, along the line joining the Sun and the Earth. The Sun is 3 × 10 5 times heavier than the Earth and is at a distance 2.5 × 10 4 times larger than the radius of the Earth. The escape velocity from Earth’s gravitational field is v e = 11.2 km s –1 . The minimum initial velocity (v s ) required for the rocket to be able to leave the Sun-Earth system is closest to ( Ignore the rotation and revolution of the Earth and the presence of any other planet )

1. v s = 42 km s –1
2. v s = 62 km s –1
3. v s = 22 km s –1
4. v s = 72 km s –1

Correct answer: v s = 42 km s –1

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