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Let b i > 1 for i = 1, 2, ...., 101. Suppose log e b 1 , log e b 2 , ...., log e b 101 are in Arithmetic Progression (A.P.) with the common difference log e 2. Suppose a 1 , a 2 , ... , a 101 are in A.P. such that a 1 = b 1 and a 51 = b 51 . If t = b 1 + b 2 + .... + b 51 and s = a 1 + a 2 + ..... + a 51 , then

s > t and a 101 > b 101
s > t and a 101 < b 101
s < t and a 101 > b 101
s < t and a 101 < b 101

Correct answer: s > t and a 101 < b 101

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