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Let – 6 π < θ < – 12 π . Suppose α 1 and β 1 are the roots of the equation x 2 – 2x sec θ + 1 = 0 and α 2 and β 2 are the roots of the equation x 2 + 2x tan θ – 1 = 0. If α 1 > β 1 and α 2 > β 2 , then α 1 + β 2 equals
- 2(sec θ – tan θ )
- 2 sec θ
- –2 tan θ
- 0
Correct answer: –2 tan θ
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