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Consider the lines L 1 : 2 1 x − = 1 y − = 1 3 z + , L 2 : 1 4 x − = 1 3 y + = 2 3 z + and the planes P 1 : 7x + y + 2z = 3, P 2 : 3x + 5y – 6z = 4. Let ax + by + cz = d be the equation of the plane passing through the point of intersection of lines L 1 and L 2 , and perpendicular to planes P 1 and P 2 . Match List-I with List-II and select the correct answer using the code given below the lists : List-I List-II (P) a = (1) 13 (Q) b = (2) –3 (R) c = (3) 1 (S) d = (4) –2 Codes : P Q R S

1. 3 2 4 1
2. 1 3 4 2
3. 3 2 1 4
4. 2 4 1 3

Correct answer: 3 2 4 1

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