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Let complex numbers α and α 1 lie on circles (x – x 0 ) 2 + (y – y 0 ) 2 = r 2 and (x – x 0 ) 2 + (y – y 0 ) 2 = 4r 2 , respectively. If z 0 = x 0 + iy 0 satisfies the equation 2 |z 0 | 2 = r 2 + 2, then | α | =

1. 2 1
2. 2 1
3. 7 1
4. 3 1

Correct answer: 7 1

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