StreakPeaked· Practice

ExamsJEE AdvancedGeneral

The arrangement of X – ions around A + ion in solid AX is given in the figure (not drawn to scale). If the radius of X – is 250 pm, the radius of A + is - X – A +

  1. 104 pm
  2. 125 pm
  3. 183 pm
  4. 57 pm

Correct answer: 104 pm

Related JEE Advanced General questions

⚔️ Practice JEE Advanced General free + battle 1v1 →