Exams › JEE Advanced › Chemistry › Qualitative Inorganic Analysis
3 questions with worked solutions.
Answer: (NH4)3PO4 * 12MoO3
When a phosphate solution is treated with ammonium molybdate in excess nitric acid and warmed, a characteristic canary yellow precipitate of ammonium phosphomolybdate, (NH4)3PO4 * 12MoO3, is formed, confirming the presence of phosphate ions.
Q2. In the qualitative analysis of cations, in which groups are the cations precipitated as sulphides?
Answer: Group II and IV
In the standard scheme of qualitative cation analysis: Group II (Cu2+, Pb2+, Bi3+, Cd2+, As3+, Sb3+, Sn2+) are precipitated as insoluble sulphides by passing H2S in dilute HCl. Group III (Fe3+, Al3+, Cr3+) are precipitated as hydroxides by NH4OH. Group IV (Co2+, Ni2+, Mn2+, Zn2+) are precipitated as sulphides in ammoniacal solution (NH4OH + NH4Cl + H2S). So sulphide precipitation occurs in Group II and Group IV.
Answer: Group II and IV
In qualitative analysis, Group II cations (Cu2+, Pb2+, Bi3+, etc.) are precipitated as sulfides by passing H2S in dilute HCl medium. Group IV cations (Co2+, Ni2+, Zn2+, Mn2+) are precipitated as sulfides by ammonium sulfide ((NH4)2S) in ammoniacal medium.