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In the molecule CH3-CH=CH-C(triple bond)N, the carbons are numbered I (CH3), II (=CH), III (CH=), IV (C of nitrile). Which carbon is the most electronegative (has the greatest s-character / most electron-attracting hybridization)?
- I
- II
- III
- IV
Correct answer: IV
Solution
The nitrile carbon (IV) is sp-hybridized with 50% s-character, the highest among the four, so it is the most electronegative carbon.
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