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Iron halides of the types FeX3 and FeY2 are known to exist. The valid sets of halogens X and Y are:

1. x = F, Cl, Br, I and y = F, Cl, Br
2. x = F, Cl, Br and y = F, Cl, Br, I
3. x = Cl, Br, I and y = F, Cl, Br, I
4. x = F, Cl, Br, I and y = F, Cl, Br, I

Correct answer: x = F, Cl, Br and y = F, Cl, Br, I

Solution

All four dihalides (FeF2, FeCl2, FeBr2, FeI2) exist, but among trihalides FeI3 does not exist because I⁻ reduces Fe(3+) to Fe(2+); hence X = F, Cl, Br and Y = F, Cl, Br, I.

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