Exams › JEE Advanced › Chemistry

Match each 3d-series metal ion in Column I with its correct characteristic in Column II. Column I: (P) Ni2+ (Q) Cr2+ (R) V2+ (S) Ti4+ Column II: (1) gives a blue aqueous solution (2) has half-filled t2g orbitals in an octahedral complex (3) is a diamagnetic ion (4) has spin-only magnetic moment mu = 2.84 B.M. Choose the correct matching code for P, Q, R, S.

1. P-4, Q-2, R-1, S-3
2. P-3, Q-1, R-2, S-4
3. P-4, Q-1, R-2, S-3
4. P-1, Q-2, R-4, S-3

Correct answer: P-4, Q-1, R-2, S-3

Solution

Ni2+ (d8, 2 unpaired) gives mu = 2.84 B.M.; Cr2+ in low-spin/Cu2+-like blue solutions is associated with the blue colour; V2+ (d3) has half-filled t2g; Ti4+ (d0) is diamagnetic.

Related JEE Advanced Chemistry questions

• The count of d-electrons in Fe2+ differs from the number of:
• Which sequence of reactions accurately depicts the chemical processes involving iron and its associated compounds?
• When H2S interacts with an acidic solution of K2Cr2O7, which of the following compounds is not produced?
• When an excess amount of sodium thiosulfate is combined with copper sulfate in water, the resulting product is:
• Among the given lanthanoid ions, which one exhibits diamagnetic behavior? (Atomic numbers: Ce = 58, Sm = 62, Eu = 63, Yb = 70)
• Which of these statements is accurate?

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →