Exams › JEE Advanced › Chemistry

125 mL of an 8% w/w NaOH solution (specific gravity = 1) is mixed with 125 mL of a 10% w/v HCl solution. What will be the nature of the resulting solution?

1. Acidic
2. Basic
3. Neutral
4. Cannot be predicted

Correct answer: Acidic

Solution

Moles NaOH = (8/100 * 125)/40 = 0.25 mol; moles HCl = (10/100 * 125)/36.5 = 0.342 mol. HCl is in excess, so the solution is acidic.

Related JEE Advanced Chemistry questions

• Which of the following contains the highest number of molecules?
• An organic compound with identical empirical and molecular formulas consists of 20% carbon, 6.7% hydrogen, 46.7% nitrogen, and the remainder as oxygen. When heated, it releases ammonia and leaves behind a solid residue. This residue produces a violet color when treated with an alkaline copper sulfate solution. Identify the compound.
• Which of the following statements accurately describe a hydrogen peroxide solution with a concentration of 17 g/L?
• The total energy needed to break all three P−H bonds in PH3(g) is 954 kJ mol⁻¹. What is the energy required to break a single P−H bond?
• Which of the following represents the balanced equation for the Calvin cycle in photosynthesis, showing the conversion of carbon dioxide into glucose?
• A substance H₂X with a molecular mass of 80 g is mixed into a liquid with a density of 0.4 g/ml. If the volume remains constant during dissolution, what is the molality of a solution with 3.2 molarity?

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →