Methanol self-ionizes as CH3OH CH3O- + H+. For a 0.5 M methanol solution, the equilibrium concentration of H+ is found to be 2.5 x 10⁻⁴ M. Calculate the percentage dissociation of methanol.

Question

Methanol self-ionizes as CH3OH <=> CH3O- + H+. For a 0.5 M methanol solution, the equilibrium concentration of H+ is found to be 2.5 x 10⁻⁴ M. Calculate the percentage dissociation of methanol.

Accepted Answer

0.05%. Since each ionized methanol produces one H+, the fraction dissociated is [H+]/0.5, and multiplying by 100 gives 0.05%.

Methanol self-ionizes as CH3OH <=> CH3O- + H+. For a 0.5 M methanol solution, the equilibrium concentration of H+ is found to be 2.5 x 10⁻⁴ M. Calculate the percentage dissociation of methanol.

Solution

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