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What volume of 0.2 M NaOH is required for the complete neutralisation of 0.49 g of orthophosphoric acid (H3PO4)?

1. 75 ml
2. 300 ml
3. 0.075 ml
4. 50 ml

Correct answer: 75 ml

Solution

0.49 g H3PO4 = 0.005 mol needs 0.015 mol NaOH; at 0.2 M, V = 0.015/0.2 = 0.075 L = 75 mL.

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