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A nitric acid (HNO3) sample has density 1.4 g/mL and is 63% HNO3 by mass. Calculate its molarity. (Molar mass of HNO3 = 63 g/mol.)

1. 14 M
2. 7 M
3. 12 M
4. 10 M

Correct answer: 14 M

Solution

Using the standard formula for molarity from density and mass percent gives 10*1.4*63/63 = 14 M.

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