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How much water must be added to 200 cc of a 0.5 M (semimolar) NaOH solution to dilute it exactly to 0.1 M (decimolar)?

1. 1000 cc
2. 400 cc
3. 800 cc
4. 600 cc

Correct answer: 800 cc

Solution

Dilution gives final volume 1000 cc from M1V1 = M2V2, so water added = 1000 - 200 = 800 cc.

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