Exams › JEE Advanced › Chemistry

100 mL of a 20.8% (w/v) BaCl2 solution is mixed with 50 mL of a 9.8% (w/v) H2SO4 solution. Find the mass of BaSO4 precipitated. (Ba = 137, Cl = 35.5, S = 32, H = 1, O = 16)

1. 11.65 g
2. 33.2 g
3. 23.3 g
4. 30.6 g

Correct answer: 11.65 g

Solution

H2SO4 is limiting at 0.05 mol, producing 0.05 mol BaSO4 of mass 11.65 g.

Related JEE Advanced Chemistry questions

• Which of the following contains the highest number of molecules?
• An organic compound with identical empirical and molecular formulas consists of 20% carbon, 6.7% hydrogen, 46.7% nitrogen, and the remainder as oxygen. When heated, it releases ammonia and leaves behind a solid residue. This residue produces a violet color when treated with an alkaline copper sulfate solution. Identify the compound.
• Which of the following statements accurately describe a hydrogen peroxide solution with a concentration of 17 g/L?
• The total energy needed to break all three P−H bonds in PH3(g) is 954 kJ mol⁻¹. What is the energy required to break a single P−H bond?
• Which of the following represents the balanced equation for the Calvin cycle in photosynthesis, showing the conversion of carbon dioxide into glucose?
• A substance H₂X with a molecular mass of 80 g is mixed into a liquid with a density of 0.4 g/ml. If the volume remains constant during dissolution, what is the molality of a solution with 3.2 molarity?

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →