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A 2 M aqueous solution of NH4Cl (density = 3.107 g/mL) is fully dissociated as NH4Cl -> NH4+ + Cl-. Calculate the molality of each ion in the solution. (Molar mass of NH4Cl = 53.5)
- 0.667 m each
- 2.0 m each
- 1.0 m each
- 0.333 m each
Correct answer: 0.667 m each
Solution
Per litre the solution has 3 kg water and 2 mol salt, giving molality 0.667 m for the salt, hence 0.667 m for each ion.
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