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A stock solution of HCl is 29.2% (w/w) with density 1.25 g/mL (molar mass of HCl = 36.5 g/mol). What volume (in mL) of this stock is needed to prepare 200 mL of 0.4 M HCl?

1. 8 mL
2. 4 mL
3. 16 mL
4. 10 mL

Correct answer: 8 mL

Solution

Stock molarity = (29.2*1.25*10)/36.5 = 10 M; using M1V1 = M2V2 gives V1 = (0.4*200)/10 = 8 mL.

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