Exams › JEE Advanced › Chemistry
A solution is made by mixing 36 g of water with 46 g of glycerine, C3H5(OH)3. Find the mole fraction of glycerine. (Molar masses: water = 18, glycerine = 92)
- 0.20
- 0.46
- 0.36
- 0.40
Correct answer: 0.20
Solution
With 2 mol water and 0.5 mol glycerine, x(glycerine) = 0.5/(2 + 0.5) = 0.5/2.5 = 0.20.
Related JEE Advanced Chemistry questions
- Two liquids P and Q create an ideal solution. At 300 K, the vapor pressure of a solution with 1 mole of P and 3 moles of Q is 550 mmHg. If 1 mole of Q is added to this mixture at the same temperature, the vapor pressure rises by 10 mmHg. What are the vapor pressures of pure P and Q (in mmHg)?
- Two liquids, A and B, form an ideal mixture. At 30°C, a solution with 1 mole of A and 2 moles of B has a total vapor pressure of 250 mmHg. When 1 additional mole of A is added to this mixture, the vapor pressure rises to 300 mmHg. What are the vapor pressures of pure A and pure B at 30°C?
- A compound M X₂ separates into M²⁺ and X⁻ ions in water, with a dissociation extent (α) of 0.5. What is the ratio of the actual freezing point depression of the solution to the freezing point depression if no dissociation occurred?
- On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is ____.
(Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol⁻¹ and 5.12 K kg mol⁻¹, respectively)
- At 25°C, liquids A and B create an ideal solution for all proportions of A and B. Two mixtures with mole fractions of A as 0.25 and 0.50 exhibit total vapor pressures of 0.3 bar and 0.4 bar, respectively. Determine the vapor pressure of pure liquid B in bar.
- The ratio of solubilities of N2 and O2 gases in water from air at 25 degrees C and 1 atm total pressure is (given that air contains 80% N2 and 20% O2 by volume, and Henry's law constants K_H(N2) = 8.42 * 10⁴ atm and K_H(O2) = 4.46 * 10⁴ atm in terms of mole fraction):
⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →