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ExamsJEE AdvancedChemistry

Arrange H3PO2, H3PO4, H3PO3 and H4P2O6 in decreasing order of the oxidation number of the phosphorus atom.

  1. H3PO4 > H4P2O6 > H3PO3 > H3PO2
  2. H3PO3 > H3PO2 > H3PO4 > H4P2O6
  3. H3PO2 > H3PO3 > H4P2O6 > H3PO4
  4. H3PO4 > H3PO2 > H3PO3 > H4P2O6

Correct answer: H3PO4 > H4P2O6 > H3PO3 > H3PO2

Solution

The oxidation states are H3PO2 = +1, H3PO3 = +3, H3PO4 = +5 and H4P2O6 = +4, so the decreasing order is +5 > +4 > +3 > +1.

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