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At 700 K the equilibrium ClF3(g) <=> ClF(g) + F2(g) has Kp = 0.2 atm. If initially only ClF3 is present at a partial pressure of 0.150 atm, find the equilibrium partial pressure of ClF3.

1. 0.027 atm
2. 0.123 atm
3. 0.075 atm
4. 0.150 atm

Correct answer: 0.027 atm

Solution

Solving x²/(0.15 - x) = 0.2 gives x = 0.123 atm, so the equilibrium partial pressure of ClF3 = 0.150 - 0.123 = 0.027 atm.

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