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Three moles of diborane (B2H6) react completely with excess methanol. How many moles of the boron-containing product are formed?

1. 6
2. 3
3. 2
4. 9

Correct answer: 6

Solution

Each mole of B2H6 gives 2 moles of trimethyl borate, so 3 moles of B2H6 give 6 moles of B(OCH3)3.

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