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For the decomposition NH2COONH4(s) <-> 2NH3(g) + CO2(g), the equilibrium constant is Kp = 2.9 * 10⁻⁵ atm³. Starting from 1 mol of the solid, what is the total pressure at equilibrium?

1. 38.8 * 10⁻² atm
2. 1.94 * 10⁻² atm
3. 5.82 * 10⁻² atm
4. 7.66 * 10⁻² atm

Correct answer: 5.82 * 10⁻² atm

Solution

With p(NH3) = 2P/3 and p(CO2) = P/3, Kp = (4/27)P³ = 2.9*10⁻⁵, giving P approximately 5.82*10⁻² atm.

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