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For the dissociation 2NH3(g) <-> N2(g) + 3H2(g), the vapour density of the equilibrium mixture is 6.0. What is the percentage dissociation of ammonia?

1. 13.88
2. 58.82
3. 41.66
4. None of these

Correct answer: 41.66

Solution

Using D0/D = 1 + alpha (since 2 mol NH3 give 4 mol gas, total moles factor (1+alpha)), 8.5/6 = 1 + alpha gives alpha = 0.4166, i.e. 41.66%.

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