One mole of A(g) is placed in a closed rigid 1 litre vessel at constant temperature, where the equilibria A(g) B(g) + C(g) (Kc1) and C(g) D(g) + B(g) (Kc2) are established. The total pressure at equilibrium is twice the initial pressure, and [C]eq / [B]eq = 1/5. Find Kc2 / Kc1.

Question

One mole of A(g) is placed in a closed rigid 1 litre vessel at constant temperature, where the equilibria A(g) <-> B(g) + C(g) (Kc1) and C(g) <-> D(g) + B(g) (Kc2) are established. The total pressure at equilibrium is twice the initial pressure, and [C]eq / [B]eq = 1/5. Find Kc2 / Kc1.

Accepted Answer

4. From total moles = 2 we get x + y = 1, and [C]/[B] = (x-y)/(x+y) = 1/5 gives x = 0.6, y = 0.4; then Kc1 = [B][C]/[A] = 0.5 and Kc2 = [D][B]/[C] = 2, so the ratio is 4.

One mole of A(g) is placed in a closed rigid 1 litre vessel at constant temperature, where the equilibria A(g) <-> B(g) + C(g) (Kc1) and C(g) <-> D(g) + B(g) (Kc2) are established. The total pressure at equilibrium is twice the initial pressure, and [C]eq / [B]eq = 1/5. Find Kc2 / Kc1.

Solution

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