For the equilibrium 2SO2(g) + O2(g) 2SO3(g) in a 10 L flask, Kc = 100 mol⁻¹ L. (a) If the moles of SO3 equal the moles of SO2, how many moles of O2 are present? (b) If the moles of SO3 are twice the moles of SO2, how many moles of O2 are present?

Question

For the equilibrium 2SO2(g) + O2(g) <-> 2SO3(g) in a 10 L flask, Kc = 100 mol⁻¹ L. (a) If the moles of SO3 equal the moles of SO2, how many moles of O2 are present? (b) If the moles of SO3 are twice the moles of SO2, how many moles of O2 are present?

Accepted Answer

(a) 1 mol, (b) 2 mol. From Kc = [SO3]²/([SO2]²[O2]) the oxygen concentration is (ratio)²/Kc; doubling the SO3:SO2 ratio quadruples the required O2, so part (b) needs more O2 than part (a).

For the equilibrium 2SO2(g) + O2(g) <-> 2SO3(g) in a 10 L flask, Kc = 100 mol⁻¹ L. (a) If the moles of SO3 equal the moles of SO2, how many moles of O2 are present? (b) If the moles of SO3 are twice the moles of SO2, how many moles of O2 are present?

Solution

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