In a 7.0 L evacuated chamber, 0.50 mol H2 and 0.50 mol I2 react at 427 deg C according to H2(g) + I2(g) 2HI(g), with Kc = 49. What is the partial pressure (in atm) of HI in the equilibrium mixture?

Question

In a 7.0 L evacuated chamber, 0.50 mol H2 and 0.50 mol I2 react at 427 deg C according to H2(g) + I2(g) <=> 2HI(g), with Kc = 49. What is the partial pressure (in atm) of HI in the equilibrium mixture?

Accepted Answer

6.385. Solving gives x = 0.0556 mol per unit so [HI] forms 0.778 mol; using PV = nRT at 700 K and 7 L gives P(HI) ~ 6.39 atm.

In a 7.0 L evacuated chamber, 0.50 mol H2 and 0.50 mol I2 react at 427 deg C according to H2(g) + I2(g) <=> 2HI(g), with Kc = 49. What is the partial pressure (in atm) of HI in the equilibrium mixture?

Solution

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