A 7.0 L evacuated chamber contains 0.50 mol H2 and 0.50 mol I2 reacting at 427 C. For H2(g) + I2(g) 2HI(g), Kc = 49 at this temperature. What is the total pressure (in atm) inside the chamber at equilibrium?

Question

A 7.0 L evacuated chamber contains 0.50 mol H2 and 0.50 mol I2 reacting at 427 C. For H2(g) + I2(g) <=> 2HI(g), Kc = 49 at this temperature. What is the total pressure (in atm) inside the chamber at equilibrium?

Accepted Answer

8.21. Because the reaction has equal moles of gas on both sides, the total number of moles (1.0 mol) is unchanged at equilibrium, so the total pressure = nRT/V = (1.0)(0.0821)(700)/7.0 = 8.21 atm.

A 7.0 L evacuated chamber contains 0.50 mol H2 and 0.50 mol I2 reacting at 427 C. For H2(g) + I2(g) <=> 2HI(g), Kc = 49 at this temperature. What is the total pressure (in atm) inside the chamber at equilibrium?

Solution

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