Exams › JEE Advanced › Chemistry
Correct answer: Pb2+
Pb2+ (from Pb, [Xe]4f14 5d10 6s2 6p2) loses the two 6p electrons to give...5d10 6s2, i.e. an 18-electron shell plus the 6s² inert pair = (18+2). Cd2+ has an 18-electron configuration only, Bi3+ also retains an s² pair but the standard textbook answer here is Pb2+.