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Two potassium salts S1 and S2 undergo the following reactions: - An aromatic amine reacted with S1 under diazotization conditions (dil. HCl, ice-cold) gives diazonium salt P1; P1 undergoes azo coupling in mildly acidic conditions to give an azo dye. - CuSO4(aq) + S2 gives a precipitate P2, K2SO4, and a poisonous gas G. - P1 and P2 together participate in Sandmeyer's reaction. Identify salt S2.
- KCN
- KBr
- KNO2
- NaCN
Correct answer: KCN
Solution
S2 is KCN because: CuSO4 + 2KCN -> Cu(CN)2 + K2SO4; Cu(CN)2 decomposes to CuCN (P2) + 1/2 (CN)2. Cyanogen (CN)2 is the poisonous gas G. P1 (diazonium salt) + CuCN gives aryl nitrile via Sandmeyer's reaction. NaCN is eliminated since S2 must be a potassium salt (K2SO4 is produced).
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