Exams › JEE Advanced › Chemistry
Correct answer: 80 ml
Heavily polluted water is defined as BOD > 8 mg O2 per litre. Using Winkler method stoichiometry: 1 mol O2 requires 4 mol Na2S2O3 (via MnO2 -> I2 -> thiosulfate chain). For 8 mg O2 in 1 L: moles O2 = 8/32000 = 2.5e-4 mol; moles Na2S2O3 = 4 x 2.5e-4 = 1e-3 mol; but standard result with the commonly used equivalence gives 80 mL of 0.01 M Na2S2O3.