Exams › JEE Advanced › Chemistry
Ore X of metal M undergoes ROASTING to form a roasted ore, which is then heated with X in the absence of O2 to give metal M. Ore Y of the same metal undergoes CALCINATION to form a calcined ore, which on heating with X in the absence of O2 also gives M. Which option correctly identifies X and Y?
- X = Chalcocite, Y = Malachite
- X = Galena, Y = Cerussite
- X = Zinc blende, Y = Calamine
- (A) and (B) both are correct
Correct answer: (A) and (B) both are correct
Solution
Auto-reduction is the standard route for extracting Cu and Pb from their sulphide/carbonate ores. Both option A (Cu system) and option B (Pb system) satisfy all conditions in the question, making D the correct answer.
Related JEE Advanced Chemistry questions
- Sulfide ores are common for the metals -
- When Cu₂S is heated, which of the following substances produces copper metal?
- Galena, a lead ore, undergoes partial oxidation when air is passed through it at elevated temperatures. Afterward, air flow is stopped, and heating continues in a sealed furnace, allowing self-reduction to occur. What is the mass (in kg) of lead formed per kilogram of oxygen used? (Atomic masses in g/mol: O = 16, S = 32, Pb = 207)
- Identify the chemical compositions of calamine, malachite, magnetite, and cryolite in the correct sequence.
- A mixture of cations is treated with H2S gas in an acidic solution. Which group of cations will form insoluble sulfide precipitates under these conditions?
- Which of the following pairs of metals is correctly matched with its commercial extraction method?
⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →