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ExamsJEE AdvancedChemistry

Match the metallurgical changes in Column-I with their properties in Column-II. Column-I (Metallurgical change): (A) CaCO3 -> CaO + CO2 (B) ZnS + O2 -> ZnO + SO2 (C) C + O2 -> CO2 (D) Fe2O3·xH2O --heat--> Fe2O3 Column-II (Properties): (P) Non-redox change (Q) Endothermic process (R) Exothermic process (S) Redox change (T) Calcination

  1. A-P,Q; B-R,S,T; C-R,S; D-P,Q
  2. A-Q,S,T; B-R,S; C-R,S; D-P,Q
  3. A-Q,T; B-R,S; C-R,S; D-P,Q
  4. A-P,Q,T; B-R,S; C-R,S; D-Q

Correct answer: A-Q,T; B-R,S; C-R,S; D-P,Q

Solution

(A) CaCO3 -> CaO + CO2: no change in oxidation states (non-redox, P), endothermic (Q), calcination (T). (B) ZnS + O2 -> ZnO + SO2: Zn goes from -2 to +2 (redox, S), exothermic (R), this is roasting not calcination. (C) C + O2 -> CO2: C is oxidised 0->+4, O is reduced 0->-2 (redox, S), exothermic (R). (D) Fe2O3·xH2O -> Fe2O3: loss of water, non-redox (P), endothermic (Q). Best match is A-P,Q,T; B-R,S; C-R,S; D-P,Q = option D.

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